16.1t^2-120t+100=0

Solution for 16.1t^2-120t+100=0 equation:

16.1t^2-120t+100=0

a = 16.1; b = -120; c = +100;
Δ = b2-4ac
Δ = -1202-4·16.1·100
Δ = 7960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-\sqrt{7960}}{2*16.1}=\frac{120-\sqrt{7960}}{32.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+\sqrt{7960}}{2*16.1}=\frac{120+\sqrt{7960}}{32.2}
$